[19:13:13] <gsingh93> is a typecast a unary operator?
[19:13:23] <gsingh93> #showerthoughts
[20:19:35] <clinth> no
[20:20:05] <clinth> because there's both the type and the thing to cast
[20:21:09] <clinth> now I guess I can see an argument for it being unary
[20:21:29] <clinth> but only in the sense that usually you have to explicitly specify the type if you're over riding it, for example
[21:49:44] <woodruffw> a typecast only has one (l|r)value, so in that sense it's unary
[21:53:03] <woodruffw> this is interesting: https://stackoverflow.com/questions/22236226/is-typecasting-a-unary-operation
[21:53:04] <yossarian-bot> Title: c - Is typecasting a unary operation? - Stack Overflow